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Question: A coil has 1000 turns and 500 cm<sup>2</sup> as it's area. The plane of the coil is placed at right ...

A coil has 1000 turns and 500 cm2 as it's area. The plane of the coil is placed at right angles to a magnetic induction field of 2 × 10–5wb/m2. The coil is rotated through 1800 in 0.2 sec. The average emf induced in the coil in mV is

A

5

B

10

C

15

D

20

Answer

10

Explanation

Solution

e=−NBA(cos⁡θ2−cos⁡θ1)te = - \frac{NBA(\cos\theta_{2} - \cos\theta_{1})}{t}

Initially θ1 = 00 and finally θ2 = 1800 so

e=−1000×2×10−5×500×10−4(cos⁡180o−cos⁡0o)0.2=10−2Ve = - \frac{1000 \times 2 \times 10^{- 5} \times 500 \times 10^{- 4}(\cos 180^{o} - \cos 0^{o})}{0.2} = 10^{- 2}V = 10 mV.