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Physics Question on Atoms

A closest distance of approach of an ∝\propto particle traveling with a velocity v towards Al13Al_{13} nucleus is d. The closest distance of approach of an alpha particle traveling with velocity 4V towards Fr26Fr_{26} nucleus is

A

d/2

B

d/4

C

d/8

D

d/16

Answer

d/8

Explanation

Solution

12mν2=14πε0×q1 q2r\frac{1}{2} m \nu^2 = \frac{1}{4 \pi \varepsilon_0} \times \frac{q_1 \, q_2}{r} rαz2ν2r \alpha \frac{z^2}{\nu^2}