A closed organ pipe of length 1.2 m vibrates in its first ov... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A closed organ pipe of length 1.2 m vibrates in its first overtone mode. The pressure variation is maximum at

A

0.4 m from the open end

B

0.4 m from the closed end

C

Both (a) and (b)

D

0.8 m from the open end

Answer

0.4 m from the open end

Explanation

Solution

In first overtone mode $\hspace10mm l= \frac{3\lambda}{4}$ $\hspace10mm \frac{\lambda}{4}=\frac{l}{3}$ $\hspace15mm =\frac{12}{3}=0.4\, m$ Pressure variation will be maximum displacement nodes, ie, at 0.4 m from the end.