Question

A closed Gaussian surface in form of a cone is formed in a region of uniform electric field as shown. The electric flux through the cone is

• A. $\pi R^2E$
• B. $2\pi RE$
• C. $2\pi R^2E$
• D. Zero

Answer 1

Answer: (D)

Zero

Answer 2

For any closed surface that encloses no charge, Gauss's law states that the net electric flux is zero. Since the cone encloses no charge, the net flux through it is

$\Phi = \frac{q_{\text{enc}}}{\varepsilon_0} = 0$.

Thus, the correct option is Zero.