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Question

Physics Question on Sound Wave

A closed and an open organ pipe have same lengths. If the ratio of frequencies of their seventh overtones is (a1a)\left(\frac{a-1}{a}\right), then the value of aa is ______.

Answer

For a closed organ pipe}, the frequency of the seventh overtone is:
fc=(2n+1)v4,n=7.f_c = (2n + 1) \frac{v}{4\ell}, \quad n = 7.
fc=15v4.f_c = 15 \frac{v}{4\ell}.
For an open organ pipe, the frequency of the seventh overtone is:
fo=(n+1)v2,n=7.f_o = (n + 1) \frac{v}{2\ell}, \quad n = 7.
fo=8v2.f_o = 8 \frac{v}{2\ell}.
The ratio is:
fcfo=1516=a1a.\frac{f_c}{f_o} = \frac{15}{16} = \frac{a - 1}{a}.
Solving:
a=16.a = 16.
Final Answer: 1616.

Explanation

Solution

For a closed organ pipe}, the frequency of the seventh overtone is:
fc=(2n+1)v4,n=7.f_c = (2n + 1) \frac{v}{4\ell}, \quad n = 7.
fc=15v4.f_c = 15 \frac{v}{4\ell}.
For an open organ pipe, the frequency of the seventh overtone is:
fo=(n+1)v2,n=7.f_o = (n + 1) \frac{v}{2\ell}, \quad n = 7.
fo=8v2.f_o = 8 \frac{v}{2\ell}.
The ratio is:
fcfo=1516=a1a.\frac{f_c}{f_o} = \frac{15}{16} = \frac{a - 1}{a}.
Solving:
a=16.a = 16.
Final Answer: 1616.