Question
Question: A clock with an iron pendulum keeps correct time at \(20\) \({}^{\text{0}}{\text{C}}\). How much tim...
A clock with an iron pendulum keeps correct time at 20 0C. How much time will its loss or gain in a day if the temperature changes to 40 0C? Thermal coefficient of linear expansion α=0.000012 per0C.
Solution
To solve this question, we use the basic theory of Thermal expansion. As we know Thermal expansion occurs when an object expands and becomes larger due to a change in the object's temperature. Similarly, in this case it will affect the operation of the clock when in a day if the temperature changes to 400C. Some basic formulas are used to get our desired result in this problem.
Formula used- ΔT=21TαΔθ
Where,
T is time period
ΔT is change in time period
Δθ is change in temperature
α is coefficient of linear expansion
Complete step-by-step answer:
Given data:
A clock which show correct time at 20°C, is now placed to 400C
Coefficient of linear expansion of the pendulum = 12 × 10−6 per 0C.
For finding, how much will it gain or lose in time:
We have the equation,
ΔT=21TαΔθ
Where,
T is time period
ΔT is change in time period
Δθ is change in temperature
α is coefficient of linear expansion
⇒ Δt=T’ΔT
But, T’ = T
⇒ Δt=21αΔθ(t)
= 21 ×0.000012×20×24×3600
= 10.37 s
At higher temperature the length of the pendulum clock will be increased as compared to the previous condition.
So, the time period will be more and it will lose the time.
Note: The expansion can occur in length of iron pendulum in which case it is called Linear Expansion. And If we take a square tile and then after heat it, the expansion will be on two fronts that is length and breadth, and it is called Area Expansion. Similarly, if we take a cube shape structure and heat it, all its sides expand and now the body experiences an increase in the overall volume of the structure and it is called Volume Expansion.