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Question: A clock with a metal pendulum beating seconds keeps correct time at 0<sup>0</sup>C. If it loses 12.5...

A clock with a metal pendulum beating seconds keeps correct time at 00C. If it loses 12.5 seconds a day at 250C, the coefficient of linear expansion of metal of pendulum is –

A

186400/ºC\frac{1}{86400}/ºC

B

143200/ºC\frac{1}{43200}/ºC

C

114400/ºC\frac{1}{14400}/ºC

D

128800/ºC\frac{1}{28800}/ºC

Answer

186400/ºC\frac{1}{86400}/ºC

Explanation

Solution

Dt = 12\frac{1}{2}at Dq

a = 2ΔttΔθ\frac{2\Delta t}{t\Delta\theta} = 2×12.586400×25\frac{2 \times 12.5}{86400 \times 25}= 186400/ºC\frac{1}{86400}/ºC