Question

A clock which keeps correct time at 20^oC, is subjected to 40^oC. If coefficient of linear expansion of the pendulum is $12 \times 10^{- 6}$/ ^oC. How much will it gain or loose in time?

• A. 10.3 sec/day
• A. (b) 20.6 sec/day
• C. 5 sec/day
• D. 20 min/day

Answer 1

Answer: (A), (A)

10.3 sec/day

Answer 2

$\frac{\Delta T}{T} = \frac{1}{2}\alpha\Delta\theta = \frac{1}{2} \times 12 \times 10^{- 6} \times (40 - 20)$;

$\Delta T = 12 \times 10^{- 5} \times 86400sec/\text{day}$ = 10.3 sec/day.