Question

A class is composed of two brothers and six other boys. In how many ways can all the boys be seated at a round table so that the two brothers are not seated besides each others ?

• A. $720$
• B. $1440$
• C. $3600$
• D. $4320$

Answer 1

Answer: (C)

$3600$

Answer 2

Total no. of ways $=\left(6-1\right)\,! \times\,^{6}p_{2}$ $=5!\times 30=120\times 30$ $=3600$