Question

A circus artist is climbing a $20\, m$ long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is $30 °$.

Answer 1

It can be observed from the figure that AB is the pole.
In ∆ABC,

$\frac{AB}{AC} = Sin 30^{\degree}$

$\frac{AB}{20} = \frac{1}2$

$AB = \frac{20}2 = 10$

Therefore, the height of the pole is $10\, m$.