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Question: A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axi...

A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plant of the disc (in kg-m2):

A

0.01

B

0.03

C

0.02

D
Answer

0.03

Explanation

Solution

32MR2=32×2×(0.1)2=0.03 kg−m2\frac { 3 } { 2 } \mathrm { MR } ^ { 2 } = \frac { 3 } { 2 } \times 2 \times ( 0.1 ) ^ { 2 } = 0.03 \mathrm {~kg} - \mathrm { m } ^ { 2 }