Question
Question: A circular loop of radius 0.3cm lies parallel to a much bigger circular loop of radius 20cm. The cen...
A circular loop of radius 0.3cm lies parallel to a much bigger circular loop of radius 20cm. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is 15cm. If a current of 2.0A flows through the smaller loop, then the flux linked with bigger loop is
(A)6×10−11Wb(B)3.3×10−11Wb(C)6.6×10−9Wb(D)9.1×10−11Wb
Solution
For calculating the magnetic flux first calculate the total magnetic field. Because magnetic flux is defined as the number of magnetic field lines passing through a given closed surface. Thus magnetic flux is the product of the magnetic field and its area. then by substituting the value of B and A we will get the magnetic flux.
Formula used:
Flux formula, Φ=BA
here, B is the magnetic field and A is the area.
B = 2(R+x)23μ0IR2 and A=πr2
Complete Answer:
Circular loop radius, r =0.3cm =3×10−3m
Bigger circular loop radius, R=20cm=0.2m
Distance, x = 15cm=0.15m
Current flowing, I=2.0A
Here we have to find the flux. For this first we have to calculate B,
B = 2(R+x)23μ0IR2=2(0.22+0.152)234π×10−7×2×0.22=3.22×10−6T
Then,
Φ=BA = 3.22×10−6 ×3.14×(3×10−3)2 =9.1×10−11Wb
Thus the option (D) is correct.
Additional information:
Magnetic flux is defined because the amount of magnetic flux the world perpendicular to the magnetic flux’s direction. It’s measurement is taken in Teslas.
Note:
The foremost significant difference between magnetic flux and therefore the magnetic flux is that the magnetic flux is that the region round the magnet where the moving charge experiences a force. Whereas the magnetic flux the strength of the magnetic lines produced by the magnet.