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Question

Physics Question on Moving charges and magnetism

A circular loop of area 1cm21\,cm^{2} , carrying a current of 10A10\,A is placed in a magnetic field of 0.1T0.1\,T perpendicular to the plane of the loop. The torque on the loop due to the magnetic field is

A

00

B

104Nm10^{-4}N\,m

C

102Nm10^{-2}N\,m

D

1Nm1\, N\,m

Answer

00

Explanation

Solution

Circular loop is placed perpendicular to the magnetic field. Therefore, angle between area vector and magnetic field is zero.
τ=IABsin0=0\therefore \tau=I A B \sin 0^{\circ}=0