Question

A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? ($\pi$ = 3.14)

Answer 1

Radius of flower bed = $\frac{66}{2}$ = $33$ $m$
Radius of flower bed and path together = $33 + 4 = 37$ $m$
Area of flower bed and path together = $3.14 × 37 × 37 = 4298.66$ $m^2$
Area of flower bed = $3.14 × 33 × 33 = 3419.46$ $m^2$
$\text{Area of path} =\text{ Area of flower bed and path together} -\text{ Area of flower bed}$
= $4298.66 - 3419.46$
= $879.20$ $m^2$

Read more: Circumference of a Circle