Question

A circular disc of radius $R$ carries surface charge density $\sigma(r)=\sigma_{0}\left(1-\frac{r}{R}\right)$, where $\sigma_{0}$ is a constant and $r$ is the distance from the center of the disc. Electric flux through a large spherical surface that encloses the charged disc completely is $\phi_{0}$. Electric flux through another spherical surface of radius $\frac{R}{4}$ and concentric with the disc is $\phi$. Then the ratio $\frac{\phi_{0}}{\phi}$ is ______

Answer 1

Then the ratio $\frac{\phi_{0}}{\phi}$ is $\underline{6.40}.$

Answer 2

Then the ratio $\frac{\phi_{0}}{\phi}$ is $\underline{6.40}.$