Question
Question: A circular disc of radius R and thickness \(\dfrac{R}{6}\) has moment inertia I about an axis passi...
A circular disc of radius R and thickness 6R has moment inertia I about an axis passing through its center perpendicular to its plane. It is melted and re-casted into a solid sphere. The moment of inertia of the sphere about its diameter is
A. I
B. 82I
C. 5I
D. 10I
Solution
In order to solve this numerical we should know the formula of volume of disc and volume of sphere. Then we can calculate the moment of inertia of the sphere. Here two cases can exist and let us calculate one by one.
Complete step by step answer:
According to the data from the question the disc is melted and it is re-casted into a solid sphere, hence it acquired a similar volume.Let V be the volume of the disc, R be the radius of the disc, M be the mass of the disc and I be the moment of inertia of of the sphere.Therefore,
Vdisc=πR2disct ⇒Vsphere=34πR3sphere
⇒Vdisc=Vsphere
⇒πR2disct=34πR3sphere
We know that, t=6Rdisc
πR2disc6Rdisc=34πR3sphere ⇒R3disc=8R3sphere ⇒Rsphere=2Rdisc
By calculating the moment of inertia of disc
Idisc=21MR2disc=I ⇒M(Rdisc)2=2I
By calculating the moment of inertia of the sphere,