Question

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is

• A. 2.01 × 10-3 T
• B. 5.64 × 10-3 T
• C. 2.64 × 10-4 T
• D. 5.64 × 10-4 T

Answer 1

Answer: (A)

2.01 × 10-3 T

Answer 2

As

$\mathrm { R } = 10 \mathrm {~cm} = 10 \times 10 ^ { - 2 } \mathrm {~m}$