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Question

Physics Question on Electromagnetic induction

A circular coil of diameter 2 cm and 100 turns is placed at the centre of a long solenoid of radius 5 cm and 10 turns/cm. The mutual inductance of the two coils will be nearest to:

A

40μH40\,\mu\,H

B

4μH4\,\mu\,H

C

40mH40\,mH

D

4mH4\,mH

Answer

40μH40\,\mu\,H

Explanation

Solution

M=μ0μ1N2A=4π×107×1000×100×π×(0.01)2=3.95×105M = \mu_0 \mu_1 \, N_2A = 4 \pi \times 10^{-7} \times 1000 \times 100 \times \pi \times (0.01)^2 = 3.95 \times 10^{-5} H