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Question: A circular coil of 300 turns and diameter 14 cm carries a current of 15 A. The magnitude of magnetic...

A circular coil of 300 turns and diameter 14 cm carries a current of 15 A. The magnitude of magnetic moment associated with the loop is

A

51.7 JT-1

B

69.2 JrT1

C

38.6 JT-1

D

19.5 JT-1

Answer

69.2 JrT1

Explanation

Solution

: Here,

N=300,I=15 A,r=7 cm=7×10−2 m\mathrm { N } = 300 , \mathrm { I } = 15 \mathrm {~A} , \mathrm { r } = 7 \mathrm {~cm} = 7 \times 10 ^ { - 2 } \mathrm {~m}

∴M=NIA=NI×πr2\therefore \mathrm { M } = \mathrm { NIA } = \mathrm { NI } \times \pi \mathrm { r } ^ { 2 }

=300×15×3.14×(7×10−2)2= 300 \times 15 \times 3.14 \times \left( 7 \times 10 ^ { - 2 } \right) ^ { 2 }

=69.2JT−1= 69.2 \mathrm { JT } ^ { - 1 }