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Question: A circular coil of 100 turns has an effective radius 0.05m and carries a current of 0.1ampere. How m...

A circular coil of 100 turns has an effective radius 0.05m and carries a current of 0.1ampere. How much work is required to turn it in an external magnetic field of 1.5 weber/m2 through 1800 about an axis perpendicular to the magnetic field. The plane of the coil is initially perpendicular to the magnetic field

A

1.8J

B

0.236J

C

2.4J

D

0.236J

Answer

0.236J

Explanation

Solution

The work done

= (μ.B)Initial(μ.B)Final\left( \overset{\rightarrow}{\mu}.\overset{\rightarrow}{B} \right)_{Initial} - \left( \overset{\rightarrow}{\mu}.\overset{\rightarrow}{B} \right)_{Final}

= μB(cos00cos1800)=2μB\mu B\left( \cos 0^{0} - \cos 180^{0} \right) = 2\mu B=2Nπa2iB2N\pi a^{2}iB

= 2×100×3.14×(0.05)2×0.1×1.52 \times 100 \times 3.14 \times (0.05)^{2} \times 0.1 \times 1.5

=0.236 Joule