Question

A circuit is made up of a resistance $1\Omega$ and inductance 0.01 H. An alternating voltage of 200 V at 50 Hz is connected then the phase difference between the current and the voltage in the circuit is

• A. $\tan^{- 1}(\pi)$
• B. $\tan^{- 1}\left( \frac{\pi}{2} \right)$
• C. $\tan^{- 1}\left( \frac{\pi}{4} \right)$
• D. $\tan^{- 1}\left( \frac{\pi}{3} \right)$

Answer 1

Answer: (A)

$\tan^{- 1}(\pi)$

Answer 2

: $\tan\varphi = \left( \frac{X_{L}}{R} \right)$

$X_{L} = \omega L = (2\pi\upsilon L) = (2\pi)(50)(0.01) = \pi\Omega$Also,

$R = 1\Omega$

$\therefore\varphi = \tan^{- 1}(\pi)$