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Question: A circuit containing a \(20\Omega\) resistor and \(0.1\mu F\)capacitor in series is connected to 230...

A circuit containing a 20Ω20\Omega resistor and 0.1μF0.1\mu Fcapacitor in series is connected to 230 V ac supply of angular frequency 100 rad s1s^{- 1}The impedance of the circuit is

A

105 Ω10^{5}\ \Omega

B

104 Ω10^{4}\ \Omega

C

106 Ω10^{6}\ \Omega

D

1010 Ω10^{10}\ \Omega

Answer

105 Ω10^{5}\ \Omega

Explanation

Solution

: Here, , R=20Ω,C=0.1μFR = 20\Omega,C = 0.1\mu F

=0.1×106F= 0.1 \times 10^{- 6}F

=107F= 10^{- 7}F

Impedance,Z=R2+1ω2C2Z = \sqrt{R^{2} + \frac{1}{\omega^{2}C^{2}}}

=202+1(100)2×(107)2= \sqrt{20^{2} + \frac{1}{(100)^{2} \times (10^{- 7})^{2}}}

=400+1010= \sqrt{400 + 10^{10}}108Ω10^{8}\Omega