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Question

Question: A circuit consists of a resistance of \(10\Omega\) and a capacitance of \(0.1\mu F\) If an alternati...

A circuit consists of a resistance of 10Ω10\Omega and a capacitance of 0.1μF0.1\mu F If an alternating emf of 100 V, 50 Hz is applied, the current in the circuit is

A

3.14 mA

B

6.28 mA

C

1.51 mA

D

7.36 mA

Answer

3.14 mA

Explanation

Solution

: XC=12πυC=12×3.14×50×0.1×106X_{C} = \frac{1}{2\pi\upsilon C} = \frac{1}{2 \times 3.14 \times 50 \times 0.1 \times 10^{- 6}}

Z=R2+XC2=100+10.28×108Z = \sqrt{R^{2} + X_{C}^{2}} = \sqrt{100 + 10.28 \times 10^{8}} =3.2×104Ω= 3.2 \times 10 ^ { 4 } \Omega Irms=εrmsZ=1003.2×104=3.14×103A3.14mAI_{rms} = \frac{\varepsilon_{rms}}{Z} = \frac{100}{3.2 \times 10^{4}} = 3.14 \times 10^{- 3}A3.14mA