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Question

Question: A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is....

A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is.

A

x2+y2axby=0x ^ { 2 } + y ^ { 2 } - a x - b y = 0

B

x2+y2+ax+by=0x ^ { 2 } + y ^ { 2 } + a x + b y = 0

C

x2+y2ax+by=0x ^ { 2 } + y ^ { 2 } - a x + b y = 0

D

x2+y2+axby=0x ^ { 2 } + y ^ { 2 } + a x - b y = 0

Answer

x2+y2axby=0x ^ { 2 } + y ^ { 2 } - a x - b y = 0

Explanation

Solution

Centre is (a2,b2)\left( \frac { a } { 2 } , \frac { b } { 2 } \right) and radius =a2+b24= \sqrt { \frac { a ^ { 2 } + b ^ { 2 } } { 4 } }