Question
Question: A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is....
A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is.
A
x2+y2−ax−by=0
B
x2+y2+ax+by=0
C
x2+y2−ax+by=0
D
x2+y2+ax−by=0
Answer
x2+y2−ax−by=0
Explanation
Solution
Centre is (2a,2b) and radius =4a2+b2
