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Question: A circle of radius \({\text{R}}\) is drawn in a uniform electric field \({\text{E}}\) as shown in th...

A circle of radius R{\text{R}} is drawn in a uniform electric field E{\text{E}} as shown in the figure. Va{V_a} , Vb{V_b} , Vc{V_c} , Vd{V_d} respectively are the potential of point AA , BB , CC , and DD at the periphery of the circle then:

(A) VA>VC,VBVD{V_A} > {V_C},{V_B} - {V_D}
(B) VA<VC,VBVD{V_A} < {V_C},{V_B} - {V_D}
(C) VA=VC,VB<VD{V_A} = {V_C},{V_B} < {V_D}
(D) VA=VC,VB>VD{V_A} = {V_C},{V_B} > {V_D}

Explanation

Solution

It is possible to consider the electric field as an electrical property associated with each point in the space where a charge is present in any form. The electric force per unit charge is also described as an electric field.

Complete Step-by-Step Solution:
According to the question,
We have been provided with a circle whose radius is R{\text{R}}
It is also stated in the question that the electric field is E{\text{E}}
In the given figure of the circle drawn inside the electric field,
It is also given that VA,VB,VC,VD{{\text{V}}_{\text{A}}},{{\text{V}}_{\text{B}}},{{\text{V}}_{\text{C}}},{{\text{V}}_{\text{D}}} are respectively the potentials of points A,B,C,D{\text{A}},{\text{B}},{\text{C}},{\text{D}}
Now, let us check the relation between the potentials of point BB and point DD .
In this case, the potential at point DD will be more than the potential at point BB .
That is
VD>VB{{\text{V}}_{\text{D}}} > {{\text{V}}_{\text{B}}} or we can rewrite this as VB<VD{{\text{V}}_{\text{B}}} < {{\text{V}}_{\text{D}}}
This is because electric field lines always flow from higher potential to lower potential.
Now, let us determine the relation about the potentials of the point AA and point CC . The potential of point AA will be equal to the potential of point CC .
That is
VA=VC{{\text{V}}_{\text{A}}} = {{\text{V}}_{\text{C}}}
In the above stated situation, the potentials are equal because both these points are situated at the exact same vertical line.
So, we can conclude that the potential at point AA is equal to the potential at point CC . And also, the potential of point BB is less than that of potential at point DD .
That is
VA=VC{V_A} = {V_C}
And VB<VD{V_B} < {V_D}

Hence, the correct option is (C.)

Note: Mathematically, the electric field is defined as a vector field that can be associated with each point in space, at which point the force per unit charge is exerted on a positive test charge at rest. The electric field is generated by electric charges or by magnetic fields that vary in time. The electric field is responsible for the attractive forces between the atomic nucleus and the electrons that then hold together in the case of the atomic scale.