Question
Question: A circle is given by \(x ^ { 2 } + y ^ { 2 } - 6 x + 8 y - 11 = 0\) and there are two points (0, 0)...
A circle is given by x2+y2−6x+8y−11=0 and there are two points (0, 0) and (1, 8). These points lie.
A
Both inside the circle
B
One outside and one inside the circle
C
Both outside the circle
D
One on and other inside the circle
Answer
One outside and one inside the circle
Explanation
Solution
From conditions that points lie inside, outside or on the circle, we see that one lies outside and one inside the circle.