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Question

Chemistry Question on Chemical Kinetics

A chemical reaction proceeds into the following steps Step I,\hspace15mm 2A \rightleftharpoons X fast Step II,\hspace10mm X + B \rightleftharpoons Y slow Step III,\hspace10mm Y + B \rightleftharpoons Product fast The law for the overall reaction is

A

rate=k[A]2rate = k [A]^2

B

rate=k[B]2rate = k [B]^2

C

rate=k[A][B]rate = k [A][B]

D

rate=k[A]2[B]rate = k [A]^2 [B]

Answer

rate=k[A]2[B]rate = k [A]^2 [B]

Explanation

Solution

dxdt=k[X][B]\frac{dx}{dt} = k ' [X][B]
From step I \hspace10mm K_{eq} = \frac{[X]}{[A]^2}
\hspace25mm [X] = K_{eq} [A]^2
\hspace25mm \frac{dx}{dt} = k' . K_{eq} [A]^2[B]
\hspace25mm = k [A]^2[B]