Solveeit Logo
Login

Question

Question: A charged water drop of radii 0.1\(\mu m\) is under equilibrium in some electric field. The charge o...

A charged water drop of radii 0.1μm\mu m is under equilibrium in some electric field. The charge on the drop is equivalent to electronic charge. The intensity of electric field is

A

1.61N/C1.61N/C

B

25.2N/C25.2N/C

C

262N/C262N/C

D

1610N/C1610N/C

Answer

1.61N/C1.61N/C

Explanation

Solution

Initially F=kQ2r2F = k\frac{Q^{2}}{r^{2}}

Finally F′=k.(Q4)2r2=F16F' = \frac{k.\left( \frac{Q}{4} \right)^{2}}{r^{2}} = \frac{F}{16}