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Question

Physics Question on Electrostatics

A charged particle qq is shot with speed vv towards another fixed charged particle QQ. It approaches QQ upto a closest distance r and then returns. If qq were given a speed 2v2v, the closest distance of approach would beA charged particle q is shot with speed v towards another fixed charged particle Q

A

rr

B

2r2r

C

r2\frac r2

D

r4\frac r4

Answer

r4\frac r4

Explanation

Solution

The correct option is (D): r4\frac r4.