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Question: A charged particle of mass \(5 \times 10^{- 5}kg\) is held stationary in space by placing it in an e...

A charged particle of mass 5×10−5kg5 \times 10^{- 5}kg is held stationary in space by placing it in an electric field of strength 107NC−110^{7}NC^{- 1} directed vertically downwards. The charge on the particle is

A

−20×10−5μC- 20 \times 10^{- 5}\mu C

B

−5×10−5μC- 5 \times 10^{- 5}\mu C

C

5×10−5μC5 \times 10^{- 5}\mu C

D

20×10−5μC20 \times 10^{- 5}\mu C

Answer

−5×10−5μC- 5 \times 10^{- 5}\mu C

Explanation

Solution

QE = mg ⇒Q=mgE=5×10−5×10107\Rightarrow Q = \frac{mg}{E} = \frac{5 \times 10^{- 5} \times 10}{10^{7}}= 5 × 10–5μC.

Since electric field is acting downward so for balance charge must be negative.