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Question

Question: A charged particle is moving in a uniform magnetic field in a circular path. Radius of circular path...

A charged particle is moving in a uniform magnetic field in a circular path. Radius of circular path is R. When energy of particle is doubled, then new radius will be

A

R2R \sqrt { 2 }

B

R3R \sqrt { 3 }

C

2 R

D

3 R

Answer

R2R \sqrt { 2 }

Explanation

Solution

r=2mKqBrKr = \frac { \sqrt { 2 m K } } { q B } \Rightarrow r \propto \sqrt { K } RR2=K2KR2=R2\Rightarrow \frac { R } { R _ { 2 } } = \sqrt { \frac { K } { 2 K } } \Rightarrow R _ { 2 } = R \sqrt { 2 }