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Question

Physics Question on Magnetic Field

A charged particle in a uniform magnetic field B=B0k^\vec{B}=B_0\hat{k} starts moving from the origin with velocity v=3i^+4k^v=3\hat{i}+4\hat{k} m/s.The trajectory of the particle and the time tt at which it reaches 2m above the x-y plane are

A

Circular path, 12\frac{1}{2}sec.

B

Helical path, 12\frac{1}{2} sec.

C

Circular path, 23\frac{2}{3}sec.

D

Helical path, 23\frac{2}{3} sec.

Answer

Circular path, 12\frac{1}{2}sec.

Explanation

Solution

The correct answer is option (A): Circular path, 12\frac{1}{2}sec.