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Question: A charged particle enters a uniform magnetic field with a velocity vector at an angle of 45<sup>0</s...

A charged particle enters a uniform magnetic field with a velocity vector at an angle of 450 with the magnetic field. The pitch of helical path followed by the particle is p. The radius of the helix will be –

A
B

2\sqrt { 2 }p

C
D
Answer
Explanation

Solution

Pitch of helical path is,

p = (v cosq) × = =

Also radius of helix is,

r = =

\ = mv2qB\frac { \mathrm { mv } } { \sqrt { 2 } \mathrm { qB } } × = 12π\frac { 1 } { 2 \pi } or r = p2π\frac { \mathrm { p } } { 2 \pi }