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Question

Physics Question on Electric charges and fields

A charge q is located at the centre of a cube. The electric flux through any face is:

A

2πq6(4πε0)\frac {2\pi q}{6(4πε_0)}

B

4πq6(4πε0)\frac {4\pi q}{6(4πε_0)}

C

πq6(4πε0)\frac {\pi q}{6(4πε_0)}

D

q6(4πε0)\frac {q}{6(4πε_0)}

Answer

4πq6(4πε0)\frac {4\pi q}{6(4πε_0)}

Explanation

Solution

Total flux passing through the close cube ϕ=qε0ϕ = \frac {q}{ε_0}
All six surfaces exhibit symmetry with respect to the charge, resulting in an equal contribution to the flux. Consequently, the flux through any single face is:
ϕ=ϕ6=q6ε0ϕ = \frac ϕ 6 = \frac {q}{6ε_0}
φface=q6ε0=4πq6(4πε0)φ_{face} = \frac {q}{6ε_0} = \frac {4\pi q}{6(4\piε_0)}

So, the correct option is (B): 4πq6(4πε0)\frac {4\pi q}{6(4πε_0)}