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Question

Question: A charge Q is distributed over a line of length L. Another point charge q is placed at a distance r ...

A charge Q is distributed over a line of length L. Another point charge q is placed at a distance r from the centre of the line distribution. Then the force experienced by q is-

A

qQ4π0(r2L2)\frac{qQ}{4\pi \in_{0}(r^{2} - L^{2})}

B

qQ4π0(r2(L/2)2)\frac{qQ}{4\pi \in_{0}(r^{2} - (L/2)^{2})}

C

qQ4π0r2\frac{qQ}{4\pi \in_{0}r^{2}}

D

qQL4π0r3\frac{qQL}{4\pi \in_{0}r^{3}}

Answer

qQ4π0(r2(L/2)2)\frac{qQ}{4\pi \in_{0}(r^{2} - (L/2)^{2})}

Explanation

Solution

dF =

F = KQqL\frac { \mathrm { KQq } } { \mathrm { L } } rL2r+L2dxx2\int _ { r - \frac { L } { 2 } } ^ { r + \frac { L } { 2 } } \frac { d x } { x ^ { 2 } } = –

=