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Question: A charge (– *q*) and another charge (+*Q*) are kept at two points *A* and *B* respectively. Keeping ...

A charge (– q) and another charge (+Q) are kept at two points A and B respectively. Keeping the charge (+Q) fixed at B, the charge (– q) at A is moved to another point C such that ABC forms an equilateral triangle of side l. The network done in moving the charge (– q) is

A

14πε0Qql\frac{1}{4\pi\varepsilon_{0}}\frac{Qq}{l}

B

14πε0Qql2\frac{1}{4\pi\varepsilon_{0}}\frac{Qq}{l^{2}}

C

14πε0Qql\frac{1}{4\pi\varepsilon_{0}}Qql

D

Zero

Answer

Zero

Explanation

Solution

Since VA=VC=kQlV_{A} = V_{C} = \frac{kQ}{l}

so W=q(VC−VA)=0W = q(V_{C} - V_{A}) = 0