Question

A charge particle q₁ is at position (2, – 1, 3) .The electrostatic force on another charge particle q₂ at (0, 0, 0) is –

• A. $\frac{q_{1}q_{2}}{56\pi\varepsilon_{0}}(2\widehat{i}–\widehat{j} + 3\widehat{k})$
• B. $\frac{q_{1}q_{2}}{56\sqrt{14}\varepsilon_{0}}(2\widehat{i}–\widehat{j}–3\widehat{k})$
• C. $\frac{q_{1}q_{2}}{56\pi\varepsilon_{0}}(\widehat{i}–2\widehat{j}–3\widehat{k})$
• D. $\frac{q_{1}q_{2}}{56\sqrt{14}\pi\varepsilon_{0}}(\widehat{i}–2\widehat{j}–3\widehat{k})$

Answer 1

Answer: (D)

$\frac{q_{1}q_{2}}{56\sqrt{14}\pi\varepsilon_{0}}(\widehat{i}–2\widehat{j}–3\widehat{k})$

Answer 2

A (q₁) ® (2, – 1, 3)

B(q₂) ® (0, 0 ,0)

=

$\overrightarrow { r _ { \mathrm { A } } }$ = $2 \hat { i } - \hat { j } + 3 \hat { k }$ ; $\overrightarrow { r _ { B } }$ = 0