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Physics Question on Moving charges and magnetism

A charge particle of 2 μC2 \,\mu C accelerated by a potential difference of 100 V100\, V enters a region of uniform magnetic field of magnitude 4 mT4 \,mT at right angle to the direction of field The charge particle completes semicircle of radius 3 cm3 \,cm inside magnetic field The mass of the charge particle is _______ ×10−18kg\times 10^{-18} kg

Answer

The correct answer is 144.
A charge particle of 2μC accelerated by a potential difference of 100

r=mv​qB=2kmqB,m=r2q2B22kr=\frac{mv​{}qB} =\frac{2km}{qB},m=\frac{r^2q^2B^2}{2k}
m=1100×3100×2×2×4×10−3×4×10−3×10−12​2×(100)×10−16m=\frac{\frac{1}{100}×\frac{3}{100}×2×2×4×10^{−3}×4×10^{−3}×10^{−12}​ }{2×(100)×10^{-16}}

=144×10−18kg