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Question

Question: A charge particle, having charge q accelerated through a potential difference V enter a perpendicula...

A charge particle, having charge q accelerated through a potential difference V enter a perpendicular magnetic field in which it experiences a force F. If V is increased to 5V, the particle will experience a force

A

F

B

5F

C

D

Answer

Explanation

Solution

12mv2=qV\frac { 1 } { 2 } m v ^ { 2 } = q V \Rightarrow v=2qVmv = \sqrt { \frac { 2 q V } { m } } . Also F=qvBF = q v B

FVF \propto \sqrt { V } which gives