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Question: A charge of + 4*μC* is kept at a distance of 50 *cm* from a charge of – 6*μC*. Find the two points w...

A charge of + 4μC is kept at a distance of 50 cm from a charge of – 6μC. Find the two points where the potential is zero

A

Internal point lies at a distance of 20 cm from 4μC charge and external point lies at a distance of 100 cm from 4μC charge.

B

Internal point lies at a distance of 30 cm from 4μC charge and external point lies at a distance of 100 cm from 4μC charge

C

Potential is zero only at 20 cm from 4μCcharge between the two charges

D

Potential is zero only at 20 cm from – 6μCcharge between the two charges

Answer

Internal point lies at a distance of 20 cm from 4μC charge and external point lies at a distance of 100 cm from 4μC charge.

Explanation

Solution

For internal point X, x1=x(Q2Q1+1)=5064+1=20cmx_{1} = \frac{x}{\left( \frac{Q_{2}}{Q_{1}} + 1 \right)} = \frac{50}{\frac{6}{4} + 1} = 20cm and for external point Y, x1=x(Q2Q11)=50641=100cmx_{1} = \frac{x}{\left( \frac{Q_{2}}{Q_{1}} - 1 \right)} = \frac{50}{\frac{6}{4} - 1} = 100cm