Question

A charge of 4 μC is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:

• A. 1 μC and 3 μC
• B. 2 μC and 2 μC
• C. 0 and 4 μC
• D. 1.5 μC and 2.5 μC

Answer 1

Answer: (B)

2 μC and 2 μC

Answer 2

The correct answer is (B) : 2 μC and 2 μC

so
$F = \frac{kq(4-q)×10^{-12}}{r^2}$
so F max will be at
q = 2µC