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Question: A charge moves in a circle perpendicular to a magnetic field. The time period of revolution is indep...

A charge moves in a circle perpendicular to a magnetic field. The time period of revolution is independent of

A

Magnetic field

B

Charge

C

Mass of the particle

D

Velocity of the particle

Answer

Velocity of the particle

Explanation

Solution

T=2πmqB⇒TαvoT = \frac { 2 \pi m } { q B } \Rightarrow T \alpha v ^ { o }