Question

A charge is uniformly distributed inside a spherical body of radius r₁ = 2r₀ having a concentric cavity of radius r₂ = r₀. (r is charge density inside the sphere). Potential of a point P at a distance $\frac{3r_{0}}{2}$ from centre is–

• A. $\frac{7\rho r_{0}^{2}}{6\varepsilon_{0}}$
• B. $\frac{101\rho r_{0}^{2}}{72\varepsilon_{0}}$
• C. $\frac{17\rho r_{0}^{2}}{72\varepsilon_{0}}$
• D. None of these

Answer 1

Answer: (B)

$\frac{101\rho r_{0}^{2}}{72\varepsilon_{0}}$

Answer 2

V_surface = $\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$ , V_surface =

from gauss theorem

$\int _ { v _ { \mathrm { s } } } ^ { \mathrm { v } } \mathrm { dV }$ = –$\sqrt { 2 }$dr

V – V_S = –$\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$dr

solving V =