Question

A charge is placed at the centre of cube of side a then flux linked with one of its given faces will be

• A. $\frac{Q}{\varepsilon_{0}}$
• B. $\frac{Q}{6\varepsilon_{0}}$
• C. $\frac{Q}{\varepsilon_{0}a^{2}}$
• D. $\frac{Q}{4\pi\varepsilon_{0}a^{2}}$

Answer 1

Answer: (B)

$\frac{Q}{6\varepsilon_{0}}$

Answer 2

Gauss?s law tells that the total flux through an area enclosing a charge Q is $\frac{Q}{\varepsilon_{0}}.$ Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of its faces is $\frac{Q}{6\varepsilon_{0}}.$