Question

A chain of length 1.5 pR and mass ‘m’ is put on a mounted half cylinder as shown in figure. Chain is pulled by vertically downward force 2 mg. Assuming surfaces to be friction less, acceleration of chain is –

• A. 2g
• B. $\frac { 2 \mathrm {~g} } { 3 }$
• C.
• D. $\frac { 5 \mathrm {~g} } { 3 }$

Answer 1

Answer: (D)

$\frac { 5 \mathrm {~g} } { 3 }$

Answer 2

Acceleration of chain is given by

a = $\frac { 2 \mathrm { mg } - \mathrm { mg } / 3 } { \mathrm {~m} }$ = $\frac { 5 \mathrm {~g} } { 3 }$