Question

A certain transverse sinusoidal wave of wavelength 20 cm is moving in the positive x direction. The transverse velocity of the particle at x = 0 as a function of the time is shown. The amplitude of the motion is:

• A. $\frac{5}{\pi}$cm
• B. $\frac{\pi}{2}$cm
• C. $\frac{10}{\pi}$cm
• D. 2π cm

Answer 1

Answer: (C)

$\frac{10}{\pi}$cm

Answer 2

V_max = Aω=5 cm/s ; T = 4 sec

⇒ ω = $\frac{2\pi}{4}$ = $\frac{\pi}{2}$

A = $\frac{5}{\pi/2} = \frac{10}{\pi}$cm.