Question
Question: A certain sample of cuprous sulphide is found to have composition \[C{{u}_{1.8}}S\] because of incor...
A certain sample of cuprous sulphide is found to have composition Cu1.8S because of incorporation of Cu2+ ions in the lattice. What is the mole percentage of the Cu2+ in total copper content in this crystal?
A. 99.8
B. 11.11
C. 88.88
D. None of these
Solution
In this type of question, you need to find out the total loss in the given sample Cu1.8S and then you can find out the mole percentage of the Cu2+ in total copper content in this crystal.
Complete step by step answer:
We know molecular formula of pure compound with Cu+ is Cu2S, but due to impurity of Cu2+ molecular formula becomes Cu1.8S.
We can write this as: Cu2SImpurity added⟷Cu1.8S
From this we can find total loss copper i.e.,
=Initial−Final
=2−1.8=0.2
Therefore, percentage of Cu2+ in total copper content is given as
=FinalInitial−Final×100
Substituting the values in above formula we get,
=1.80.2×100=11.11
Hence, mole percentage of Cu2+ in total copper content is 11.11
So, the correct answer is Option B.
Additional Information:
In both Cu2S and Cu1.8S, electrical neutrality is maintained. Atom is said to be electrically neutral when the overall charge of the atom is zero.
Copper sulphide is a chemical compound of copper and sulphur, it has the chemical formula Cu2S. It is basically found in nature as the mineral chalcocite.
Copper sulfide ores must be concentrated before they can be economically transported and smelted.
Note: You should know the chemical formula of copper sulphide so that you can easily find out the loss from the sample which is impure. Also to find the loss of percentage composition of a particular element from the given compound we subtract final composition from initial composition and divide by final. This will give the composition for percentage calculation we have to multiply it with hundred.