Question
Question: A certain reaction proceeds in sequence of three elementary steps with rate constant k<sub>1</sub>, ...
A certain reaction proceeds in sequence of three elementary steps with rate constant k1, k2& k3. If kobs= (k2k1)1/2. k3 the observed Ea is –
A
21(E2E1)+E3
B
2E3+E1
C
E3(E2E1)1/2
D
E3 + 21 [E1 –E2]
Answer
E3 + 21 E<sub>1</sub>–E<sub>2</sub>
Explanation
Solution
k0 = (K2K1)1/2× k3……..(1)
k = A e –ta/RT ……..(2)
from (1) & (2)
Ae–Ea/RT = (A2e–Ea2/RTA1e–Ea/RT)1/2⋅A3e–Ea3/RTi.e.
Ea = 21 [Ea1 – Ea2] + Ea3