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Question

Physics Question on Surface tension

A certain number of spherical drops of a liquid of radius 'r' coalesce to form a single drop of radius 'R' and volume 'V'. If 'T' is the surface tension of the liquid, then:

A

energy = 3VT(1r+1R\frac{1}{r}+\frac{1}{R}) is absorbed.

B

energy = 3VT(1r1R\frac{1}{r}-\frac{1}{R}) is released.

C

energy is neither released nor absorbed.

D

energy = 4VT(1r1R\frac{1}{r}-\frac{1}{R}) is released.

Answer

energy = 3VT(1r1R\frac{1}{r}-\frac{1}{R}) is released.

Explanation

Solution

The correct option (B): energy = 3VT(1r1R\frac{1}{r}-\frac{1}{R}) is released.