Question
Question: A certain ideal gas undergoes a polytropic process \(P{V^n} = \)constant such that the molar specifi...
A certain ideal gas undergoes a polytropic process PVn=constant such that the molar specific heat during the process is negative. If the ratio of the specific heats of the gas be γ, then the range of values of n will be:
A)0<n<γ
B)1<n<γ
C)n=γ
D)n>γ
Solution
Hint The expression for the molar specific heat in a polytropic process is given by
C=γ−1R−n−1R
We are given the question that C is negative. Hence, we are to find only those values of n for which the entire expression becomes negative.
Complete step-by-step solution :
A polytropic process is mathematically expressed as PVn=constant
Where
P is the pressure
Vis the volume
n is the polytropic index
Value of n ranges from 0 to infinity but in the situation given above, we have to find only those values of n for which molar specific heat, i.e., C is negative.
Molar specific heat is given as
C=γ−1R−n−1R
Here , R is universal gas constant and γ is the ratio of specific heats of gas.
Upon simplifying the above expression, we get
C=(γ−1)(n−1)(n−1)R−(γ−1)R=(γ−1)(n−1)nR−R−γR+R =(γ−1)(n−1)(n−γ)R
Now we will focus on three terms of the expression obtained and analyse their range, (n−γ),(n−1),(γ−1)
We have two relations
γ=CVCP and CP−CV=R
These expressions suggest that
CP>CV and hence, γ>1
So, γ−1 will always be positive.
We can conclude that for C to be negative, n−γ will be negative. That is
n−γ<0
n<γ (1)
And n−1 will be positive. i.e.,
n−1>0
n>1 (2)
From (1) and (2), we get
1<n<γ
Hence option B is correct.
Note:- For any question of the type where we are supposed to predict the values of a variable, it is a good practice to factorise the expression and then one by one evaluate each factor to get the values. Good care must be taken by solving the inequalities.